A stone is thrown at an angle of 45° above the horizontal from the top edge of a cliff with an initial speed of 15 m/s.A stop watch measures the stone's trajectory time from top of cliff to bottom to be 5.4 s.How far out from the cliff's edge does the stone travel horizontally? (g = 9.8 m/s² and air resistance is negligible) A) 57 m B) 81 m C) 202 m D) 86 m E) 200 m

Question

Quizplus · Accepted Answer

The horizontal component of the initial velocity is 15 m/s * cos(45°) = 10.6 m/s. The time of flight is 5.4 s. So the horizontal distance traveled is 10.6 m/s * 5.4 s = 57.2 m.

A Stone Is Thrown at an Angle of 45° Above