Wiley Coyote has missed the elusive road runner once again.This time,he leaves the edge of the cliff at 50.1 m/s horizontal velocity.If the canyon is 110 m deep,how far from his starting point at the edge of the cliff does the coyote land?

A) 237 m
B) 168 m
C) 336 m
D) 119 m
E) 59 m

Question

Wiley Coyote has missed the elusive road runner once again.This time,he leaves the edge of the cliff at 50.1 m/s horizontal velocity.If the canyon is 110 m deep,how far from his starting point at the edge of the cliff does the coyote land?
​
A) 237 m
B) 168 m
C) 336 m
D) 119 m
E) ​59 m

Quizplus · Accepted Answer

The time to fall 110 m is found using the formula $ t = \sqrt{\frac{2h}{g}} $, where $ h = 110 $ m and $ g = 9.8 $ m/s². This gives $ t \approx 4.74 $ s. The horizontal distance is then $ v \times t = 50.1 \times 4.74 \approx 237 $ m.

Wiley Coyote Has Missed the Elusive Road Runner Once Again