A ball is launched from ground level at 30 m/s at an angle of 25° above the horizontal.How far does it go before it is at ground level again?
A) 14 m
B) 70 m
C) 43 m
D) 86 m

Question

Quizplus · Accepted Answer

We can use the horizontal and vertical components of the velocity to solve this problem.
The initial vertical velocity is v*sin(25°) and the horizontal velocity is v*cos(25°).
When the ball is at ground level again, its vertical velocity is zero.
We can use the formula vf^2 = vi^2 + 2ad with vf = 0, vi = v*sin(25°), and a = -9.8 m/s^2.
Solving for d, we get d = vi^2 / (2a) = (30*sin(25°))^2 / (2*(-9.8)) = 70.04 m.
Therefore, the ball goes 70 m before it is at ground level again. The answer is B.

A Ball Is Launched from Ground Level at 30 M/s