A 10-kg mass and a 6.0-kg mass are connected by a light string over a massless,frictionless pulley.If g = 9.8 m/s²,what is the acceleration of the system when released? A) 2.5 m/s² B) 6.5 m/s² C) 7.8 m/s² D) 9.8 m/s²

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Quizplus · Accepted Answer

The acceleration of the system can be found using the formula: a = (m1 - m2) * g / (m1 + m2), where m1 = 10 kg and m2 = 6 kg. Substituting the values, a = (10 - 6) * 9.8 / (10 + 6) = 4 * 9.8 / 16 = 2.45 m/s², which rounds to 2.5 m/s².

A 10-Kg Mass and a 6