A box is launched up a frictionless incline with an angle of elevation θ.The maximum height reached by the box is h.The box is again launched up the incline with the same initial speed it had before,but this time the angle of elevation has been increased to φ.How does the maximum height H reached this time by the box compare with the previous value h? A)H = h B)H h C)H

Question

A box is launched up a frictionless incline with an angle of elevation θ.The maximum height reached by the box is h.The box is again launched up the incline with the same initial speed it had before,but this time the angle of elevation has been increased to φ.How does the maximum height H reached this time by the box compare with the previous value h?
A)H = h
B)H > h
C)H < h
D)H​ = ((sinφ)/(sinθ))

Quizplus · Accepted Answer

The Answer of A box is launched up a frictionless incline with an angle of elevation θ.The maximum height reached by the box is h.The box is again launched up the incline with the same initial speed it had before,but this time the angle of elevation has been increased to φ.How does the maximum height H reached this time by the box compare with the previous value h?
A)H = h
B)H > h
C)H < h
D)H​ = ((sinφ)/(sinθ))

A Box Is Launched Up a Frictionless Incline with an Angle