An automobile of mass 3,000 kg moving at 45 m/s is braked suddenly with a constant braking force of 9,000 N.How far does the car travel before stopping?
A) 8 m
B) 338 m
C) 169 m
D) 507 m
E) 18 m

Question

An automobile of mass 3,000 kg moving at 45 m/s is braked suddenly with a constant braking force of 9,000 N.How far does the car travel before stopping?
A) 8 m
B) 338 m
C) 169 m
D) 507 m
E) ​18 m

Quizplus · Accepted Answer

The correct answer is B because the car travels 338 m before stopping. The formula for the distance traveled by a car before stopping is:d = (v^2) / (2 * a)where:d is the distance traveled (in meters)v is the initial velocity (in meters per second)a is the acceleration (in meters per second squared)In this case, the initial velocity is 45 m/s, the acceleration is -9,000 N / 3,000 kg = -3 m/s^2, and the distance traveled is:d = (45 m/s)^2 / (2 * -3 m/s^2) = 338 m

An Automobile of Mass 3,000 Kg Moving at 45 M/s