A hockey puck moving at 9.0 m/s coasts to a halt in 85 m on a smooth ice surface.What is the coefficient of friction between the ice and the puck?

Question

Quizplus · Accepted Answer

We can use the formula: 
d = (v^2/2μg)
where d is the distance traveled, v is the initial velocity, μ is the coefficient of friction and g is the acceleration due to gravity (9.8 m/s^2)
Rearranging the formula to solve for μ, we get: 
μ = (v^2)/(2gd)
Substituting the given values, we get: 
μ = (9.0^2)/(2 x 9.8 x 85) ≈ 0.049
Therefore, the coefficient of friction between the ice and the puck is 0.049. So, the best choice is B.

A Hockey Puck Moving at 9