An Olympic skier moving at 15.0 m/s down a 25.0° slope encounters a region of wet snow,of coefficient of friction μ_k = 0.740.How far down the slope does she go before stopping? A) 56 m B) 46 m C) 66 m D) 36 m E) 61 m

Question

Quizplus · Accepted Answer

The skier's initial kinetic energy is converted into work done against friction. Using the equation $d = \frac{v^2}{2g(\sin\theta + \mu_k \cos\theta)}$, where $v = 15.0 \, \text{m/s}$, $g = 9.8 \, \text{m/s}^2$, $\theta = 25.0^\circ$, and $\mu_k = 0.740$, the distance $d$ is calculated to be approximately 46 m.

An Olympic Skier Moving at 15