A roller coaster,loaded with passengers,has a mass of 3000 kg;the radius of curvature of the track at the bottom point of the dip is 24 m.If the vehicle has a speed of 18 m/s at this point,what force is exerted on the vehicle by the track? (g = 9.8 m/s²) A) 2.3 × 10⁴ N B) 4.7 × 10⁴ N C) 7.0 × 10⁴ N D) 1.0 × 10⁴ N

Question

Quizplus · Accepted Answer

The force exerted by the track is the sum of the gravitational force and the centripetal force. The gravitational force is mg = 3000 kg * 9.8 m/s² = 29400 N. The centripetal force is mv²/r = 3000 kg * (18 m/s)² / 24 m = 40500 N. The total force is 29400 N + 40500 N = 69900 N, which is approximately 7.0 × 10⁴ N.

A Roller Coaster,loaded with Passengers,has a Mass of 3000 Kg;the