A 15.00-kg bowling ball falls from a 3.00-m shelf.Just before hitting the floor,what will be its kinetic energy? (g = 9.80 m/s² and assume air resistance is negligible)

Question

Quizplus · Accepted Answer

The potential energy of the bowling ball due to its position on the shelf is given by:
PE = mgh = 15.00 kg x 9.80 m/s^2 x 3.00 m = 441 J

When the ball falls and reaches the ground, all of its potential energy is converted into kinetic energy. Therefore, the kinetic energy of the ball just before hitting the ground is equal to its potential energy at its initial position on the shelf:

KE = PE = 441 J

Therefore, the correct answer is (D) 441 J.

A 1500-Kg Bowling Ball Falls from a 3