A 13.0-kg box starts at rest and slides 3.5 m down a ramp inclined at an angle of 10° with the horizontal.If there is no friction between the ramp surface and crate,what is the velocity of the crate at the bottom of the ramp? (g = 9.8 m/s²) A) 11.91 m/s B) 3.45 m/s C) 8.28 m/s D) 8.22 m/s E) 68.6 m/s

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Quizplus · Accepted Answer

The velocity can be found using energy conservation. The potential energy at the top is converted to kinetic energy at the bottom. Using the formula: mgh = 0.5 * m * v^2, where h = 3.5 * sin(10°), solve for v to get approximately 3.45 m/s.

A 130-Kg Box Starts at Rest and Slides 3