A 24-N crate starting at rest slides down a rough 4-m long ramp,inclined at 29° with the horizontal.20 J of energy is lost to friction.What will be the speed of the crate at the bottom of the incline?
A) 11.4 m/s
B) 3.3 m/s
C) 1.5 m/s
D) 4.7 m/s
E) 21.6 m/s

Question

A 24-N crate starting at rest slides down a rough 4-m long ramp,inclined at 29° with the horizontal.20 J of energy is lost to friction.What will be the speed of the crate at the bottom of the incline?
A) 11.4 m/s
B) 3.3 m/s
C) 1.5 m/s
D) 4.7 m/s
E) ​21.6 m/s

Quizplus · Accepted Answer

The gravitational potential energy lost is mgh = 24 N * 4 m * sin(29°). The work done by friction is 20 J. The kinetic energy at the bottom is the initial potential energy minus the work done by friction. Use KE = 0.5 * m * v^2 to solve for v.

A 24-N Crate Starting at Rest Slides Down a Rough