I drop a 65-g golf ball from 3.0 m high.It rebounds to 1.0 m.How much energy is lost?

Name: I drop a 65-g golf ball from 3.0 m high.It rebounds to 1.0 m.How much energy is lost?
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Question

Quizplus · Accepted Answer

Explanation:The initial potential energy of the ball is:PEi = mgh = (0.065 kg)(9.8 m/s^2)(3.0 m) = 1.96 JThe final potential energy of the ball is:PEf = mgh = (0.065 kg)(9.8 m/s^2)(1.0 m) = 0.637 JThe energy lost is:ΔE = PEi - PEf = 1.96 J - 0.637 J = 1.323 JTherefore, the correct answer is C) 1.32 J.

I Drop a 65-G Golf Ball from 3