The net force acting on a 4.0-kg object is given by F_x = (10 − x)N,where F_x is in newtons and x is in meters.How much work is done on the object as it moves from x = 0 to x = 15 m? A) 5 J B) 15 J C) 37.5 J D) 18.75 J E) 28.125 J

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Quizplus · Accepted Answer

The work done is the integral of the force over the distance. Integrating F(x) = (10 - x) from x = 0 to x = 15 gives W = ∫(10 - x) dx = [10x - (x^2)/2] from 0 to 15, which equals 37.5 J.

The Net Force Acting on a 4