The net force acting on a 6.0-kg object is given by F_x = (12 - x)N,where F_x is in newtons and x is in meters.How much work is done on the object as it moves from x = 0 to x = 12 m? A) 120 J B) 72 J C) 36 J D) 18 J

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Quizplus · Accepted Answer

The work done is the integral of force over distance. Integrating F(x) = (12 - x) from x = 0 to x = 12 gives W = ∫(12 - x) dx from 0 to 12 = [12x - (x^2)/2] from 0 to 12 = (12*12 - (12^2)/2) - (12*0 - (0^2)/2) = 144 - 72 = 72 J.

The Net Force Acting on a 6