A baseball catcher puts on an exhibition by catching a 0.15-kg ball dropped from a helicopter at a height of 91 m.What is the speed of the ball just before it hits the catcher's glove 1.0 m above the ground? (g = 9.8 m/s² and ignore air resistance)

Question

Quizplus · Accepted Answer

Using the equation vf² = vi² + 2gh, we can solve for final velocity (vf):
vf² = 0 + 2(9.8 m/s²)(91 m)
vf = 42 m/s (rounded to 2 significant figures)

Therefore, the answer is C, 42 m/s.

A Baseball Catcher Puts on an Exhibition by Catching a 0.15-Kg