By how much is the energy stored in a Hooke's law spring increased when its stretch is increased from 4.00 cm to 8.00 cm?
A) 100%
B) 200%
C) 300 %
D) The correct answer is not given.

Question

Quizplus · Accepted Answer

The energy stored in a Hooke's law spring is given by the formula E = (1/2) kx^2, where k is the spring constant and x is the displacement from the equilibrium position. When the stretch is increased from 4.00 cm to 8.00 cm, the displacement (x) increases by a factor of 2. Therefore, the energy stored increases by a factor of (2)^2 = 4. This is equivalent to a percentage increase of 300% (i.e., the energy stored is quadrupled). Thus, the correct answer is C.

By How Much Is the Energy Stored in a Hooke's