A worker pushes a sled with a force of 40 N over a level distance of 6.0 m.If a frictional force of 16 N acts on the wheelbarrow in a direction opposite to that of the worker,what total work is done on the wheelbarrow?
A) 240 J
B) 216 J
C) 144 J
D) 96 J

Question

Quizplus · Accepted Answer

The total work done on the wheelbarrow is the net force multiplied by the distance. The net force is the applied force minus the frictional force: 40 N - 16 N = 24 N. Therefore, the work done is 24 N * 6.0 m = 144 J.

A Worker Pushes a Sled with a Force of 40