A 29-g bullet moving at 1,100 m/s is fired through a one-kg block of wood emerging at a speed of 150 m/s.If the block had been originally at rest and is free to move,what is its resulting speed?

Question

Quizplus · Accepted Answer

Using the conservation of momentum: initial momentum = final momentum. (0.029 kg * 1100 m/s) = (0.029 kg * 150 m/s) + (1 kg * v). Solving for v gives v = 27.6 m/s.

A 29-G Bullet Moving at 1,100 M/s Is Fired Through