A 4.0 ft by 8.0 ft sheet of plywood of uniform density and thickness lies in the 1^st quadrant with its long side along the x axis,one corner at the origin,and the diagonally opposite corner at position (x,y)= (8.0 ft,4.0 ft).The lower right 2.0 ft by 4.0 ft quarter of the sheet is removed from the sheet.What are the coordinates of the center of mass of the remaining portion of the sheet? A) (2.0 ft,4.0 ft) B) (1.0 ft,2.0 ft) C) (3.3 ft,1.7 ft) D) (3.3 ft,2.3 ft)

Question

Quizplus · Accepted Answer

The center of mass of the entire sheet is initially at (4.0 ft, 2.0 ft). When the lower right quarter (2.0 ft by 4.0 ft) is removed, the center of mass shifts towards the remaining mass. The new center of mass can be calculated using the formula for the center of mass of composite bodies, resulting in approximately (3.3 ft, 2.3 ft).

A 40 Ft by 8