A 4.0-kg mass is placed at (2.0,3.0)m,and a 7.0-kg mass is placed at (2.0,−3.0)m.What is the moment of inertia of this system of masses about the y axis?

Question

Quizplus · Accepted Answer

The moment of inertia about the y-axis is calculated using I = Σm*x². For the 4.0-kg mass at (2.0,3.0)m, I = 4.0*(2.0)² = 16 kg·m². For the 7.0-kg mass at (2.0,-3.0)m, I = 7.0*(2.0)² = 28 kg·m². Total I = 16 + 28 = 44 kg·m².

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