A majorette takes two batons and fastens them together in the middle at right angles to make an "x" shape.Each baton was 0.90 m long and each ball on the end is 0.20 kg.(Ignore the mass of the rods. )What is the moment of inertia if the arrangement is spun around an axis through the center perpendicular to both rods? A) 0.036 kg·m² B) 0.081 kg·m² C) 0.041 kg·m² D) 0.162 kg·m² E) 0.180 kg·m²

Question

Quizplus · Accepted Answer

The moment of inertia for each ball is calculated using I = mr², where m is the mass and r is the distance from the axis. Each ball is 0.45 m from the center (half of 0.90 m). So, I for one ball = 0.20 kg * (0.45 m)² = 0.0405 kg·m². There are four balls, so total I = 4 * 0.0405 kg·m² = 0.162 kg·m².

A Majorette Takes Two Batons and Fastens Them Together in the Middle