A Ferris wheel,rotating initially at an angular speed of 0.13 rad/s,accelerates over a 5.0-s interval at a rate of 0.050 rad/s².What is its angular speed after this 5.0-s interval? A) 0.25 rad/s B) 0.9 rad/s C) 0.38 rad/s D) 0.03 rad/s E) 0.19 rad/s

Question

Quizplus · Accepted Answer

Using the formula:
ωf = ωi + αt
where:
ωi = initial angular speed = 0.13 rad/s
α = angular acceleration = 0.050 rad/s^2
t = time interval = 5.0 s

Substituting the values, we get:
ωf = 0.13 + 0.050 x 5.0
ωf = 0.38 rad/s

Therefore, the final angular speed of the Ferris wheel after 5.0 s is 0.38 rad/s. Hence the correct answer is option C.

A Ferris Wheel,rotating Initially at an Angular Speed of 0