A fluid has a density of 1 040 kg/m³.If it rises to a height of 1.6 cm in a 1.5-mm diameter capillary tube,what is the surface tension of the liquid? Assume a contact angle of zero. A) 0.061 N/m B) 0.122 N/m C) 6.115 N/m D) 0.245 N/m E) 12.23 N/m

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The surface tension of the liquid can be calculated using the formula:$$P = \frac{2\gamma \cos 	heta}{r}$$where:* P is the pressure difference between the inside and outside of the capillary tube* γ is the surface tension of the liquid* θ is the contact angle between the liquid and the capillary tube* r is the radius of the capillary tubeIn this case, the pressure difference is equal to the hydrostatic pressure of the liquid column, which is given by:$$P = ho g h$$where:* ρ is the density of the liquid* g is the acceleration due to gravity* h is the height of the liquid columnSubstituting these values into the first equation, we get:$$ho g h = \frac{2\gamma \cos 	heta}{r}$$Solving for γ, we get:$$\gamma = \frac{ho g h r}{2\cos 	heta}$$Substituting the given values, we get:$$\gamma = \frac{(1040 	ext{ kg/m}^3)(9.81 	ext{ m/s}^2)(1.6 	imes 10^{-2} 	ext{ m})}{2\cos 0^\circ}$$$$\gamma = 0.061 	ext{ N/m}$$Therefore, the correct answer is A.

A Fluid Has a Density of 1 040 Kg/m3

A Fluid Has a Density of 1 040 Kg/m³