Two moles of nitrogen gas are contained in an enclosed cylinder with a movable piston.If the gas temperature is 333 K,and the pressure is 1.14 × 10⁶ N/m²,what is the volume? (R = 8.31 J/mol⋅K) A) 2.42 × 10−³ m³ B) 4.85 × 10−³ m³ C) 6.06 × 10−³ m³ D) 9.71 × 10−³ m³ E) 3.64 × 10−³ m³

Question

Quizplus · Accepted Answer

Using the ideal gas law PV = nRT, where P = 1.14 × 10^6 N/m^2, n = 2 moles, R = 8.31 J/mol⋅K, and T = 333 K, the volume V can be calculated as V = nRT/P = (2 * 8.31 * 333) / (1.14 × 10^6) = 4.85 × 10^-3 m^3.

Two Moles of Nitrogen Gas Are Contained in an Enclosed