The position of a 0.64-kg mass undergoing simple harmonic motion is given by x = (0.160 m)cos (πt/8).What is its period of oscillation?

Question

Quizplus · Accepted Answer

The period of oscillation can be found using the formula T = 2π/ω, where ω is the angular frequency. From the given equation, we can see that the angular frequency is π/8, so we have T = (2π)/(π/8) = 16 s. Therefore, the correct answer is (C) 16 s.

The Position of a 0