What is the temperature increase of 5.0 kg of water when heated by an 1,000-W immersion heater for 6 min? (c_w = 4 186 J/kg⋅°C)

Question

Quizplus · Accepted Answer

First, we need to use the formula Q = mcΔT, where Q is the heat energy transferred, m is the mass of water, c is the specific heat capacity of water (4,186 J/kg·°C), and ΔT is the temperature increase.

We can calculate the heat energy transferred as:

Q = Pt = (1,000 W)(6 min × 60 s/min) = 360,000 J

Next, we can calculate the mass of water as:

m = 5.0 kg

Finally, we can rearrange the formula to solve for ΔT:

ΔT = Q/mc = (360,000 J)/(5.0 kg × 4,186 J/kg·°C) ≈ 17.20°C

Therefore, the temperature increase of the water is approximately 17.20°C. The answer is C.

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