A windowpane is half a centimeter thick and has an area of 0.9 m².The temperature difference between the inside and outside surfaces of the pane is 14 °C.What is the rate of heat flow through this window? (Thermal conductivity for glass is 0.84 J/s⋅m⋅°C. )

Question

Quizplus · Accepted Answer

The rate of heat flow (Q/t) through a material is given by the formula: Q/t = (k * A * ΔT) / d, where k is the thermal conductivity, A is the area, ΔT is the temperature difference, and d is the thickness. Substituting the given values: Q/t = (0.84 J/s⋅m⋅°C * 0.9 m² * 14 °C) / 0.005 m = 2,100 J/s.

A Windowpane Is Half a Centimeter Thick and Has an Area