If two adjacent frequencies of an organ pipe closed at one end are 500 Hz and 700 Hz,what is the length of the organ pipe? (v_sound = 340 m/s) A) 0.85 m B) 1.25 m C) 1.50 m D) 1.70 m

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The correct answer is A.The length of an organ pipe closed at one end is given by:$$L = \frac{\lambda}{4}$$where $\lambda$ is the wavelength of the sound wave.The wavelength of a sound wave is given by:$$\lambda = \frac{v}{f}$$where $v$ is the speed of sound and $f$ is the frequency.The two adjacent frequencies are 500 Hz and 700 Hz. So, the wavelength of the sound wave is:$$\lambda = \frac{340 	ext{ m/s}}{500 	ext{ Hz}} = 0.68 	ext{ m}$$Therefore, the length of the organ pipe is:$$L = \frac{0.68 	ext{ m}}{4} = 0.17 	ext{ m}$$

If Two Adjacent Frequencies of an Organ Pipe Closed at One