A mass of 0.39 kg,hanging from a spring with a spring constant of 72 N/m,is set into an up-and-down simple harmonic motion.What is the speed of the mass when moving through the equilibrium point? The starting displacement from equilibrium is 0.14 m.

A) zero
B) 1.9 m/s
C) 2.7 m/s
D) 2.5 m/s
E) 0.3 m/s

Question

A mass of 0.39 kg,hanging from a spring with a spring constant of 72 N/m,is set into an up-and-down simple harmonic motion.What is the speed of the mass when moving through the equilibrium point? The starting displacement from equilibrium is 0.14 m.
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A) zero
B) 1.9 m/s
C) 2.7 m/s
D) 2.5 m/s
E) 0.3 m/s

Quizplus · Accepted Answer

The speed at the equilibrium point is the maximum speed, which can be calculated using the formula v_max = sqrt(k/m) * A, where k is the spring constant, m is the mass, and A is the amplitude. Substituting the given values, v_max = sqrt(72/0.39) * 0.14 = 1.9 m/s.

A Mass of 0