A 20-kg piece of aluminum (which has a specific heat of 900 J/kg · °C)is warmed so that its temperature increases by 5.0°C.How much heat was transferred into it? A) 4.5 × 10⁴ J B) 9.0 × 10⁴ J C) 1.4 × 10⁵ J D) 2.0 × 10⁵ J

Question

Quizplus · Accepted Answer

The equation to calculate the heat transferred is:
Q = m·c·ΔT
where Q is the heat transferred, m is the mass of the aluminum, c is the specific heat of aluminum, and ΔT is the change in temperature.
Substituting the given values, we get:
Q = 20 kg · 900 J/kg·°C · 5.0°C = 9.0 × 10^4 J
Therefore, the heat transferred into the piece of aluminum was 9.0 × 10^4 J, which corresponds to answer choice B.

A 20-Kg Piece of Aluminum (Which Has a Specific Heat