A puddle holds 150 g of water.If 0.75 g of water evaporates from the surface,what is the approximate temperature change of the remaining water? (L_v = 540 cal/g)

Question

Quizplus · Accepted Answer

The heat required for evaporation is given by Q = m * Lv, where m is the mass of evaporated water and Lv is the latent heat of vaporization. The temperature change can be calculated using Q = mcΔT, where c is the specific heat capacity of water (1 cal/g°C). Solving for ΔT gives ΔT = Q/(mc). Substituting the values, ΔT = (0.75 g * 540 cal/g) / (150 g * 1 cal/g°C) = 2.7°C. The temperature change is negative because the evaporation process absorbs heat, cooling the remaining water.

A Puddle Holds 150 G of Water