A bat,flying at 6 m/s toward a wall,emits a chirp at 48 kHz.If the wall reflects this sound pulse,what is the frequency of the echo received by the bat? (v_sound = 340 m/s)

Question

Quizplus · Accepted Answer

The Doppler effect formula for sound frequency received by a moving source and observer is used. The bat is both the source and observer. First, calculate the frequency heard by the wall: f' = f(v_sound + v_bat) / v_sound. Then, calculate the frequency of the echo received by the bat: f'' = f'(v_sound) / (v_sound - v_bat). This results in approximately 49.7 kHz.

A Bat,flying at 6 M/s Toward a Wall,emits a Chirp