Two moles of an ideal gas at 3.0 atm and 10°C are heated up to 100°C.If the volume is held constant during this heating,what is the final pressure?
A) 4.5 atm
B) 4.0 atm
C) 0.14 atm
D) 1.0 atm

Question

Quizplus · Accepted Answer

According to Charles's Law, when the volume of a gas is held constant, the temperature and pressure are directly proportional. Using the combined gas law, we can find the final pressure:
(P1 x V1)/T1 = (P2 x V1)/T2
where P1 = 3 atm, V1 = number of moles x gas constant x temperature = 2 mol x 0.0821 L·atm/mol·K x 283 K = 46.77 L·atm/mol, T1 = 283 K, and T2 = 373 K (100°C).
Rearranging the equation and solving for P2, we get:
P2 = (P1 x T2)/T1 = (3 atm x 373 K)/283 K = 3.95 atm ≈ 4.0 atm. Therefore, the final pressure is approximately 4.0 atm.

Two Moles of an Ideal Gas at 3