9.0 g of water in a 2.0-L pressure vessel is heated to 300°C.What is the pressure inside the container? (R = 0.082 L · atm/mol · K,one mole of water has a mass of 18 grams)

Question

Quizplus · Accepted Answer

The correct answer is A because the pressure inside the container is 12 atm. This can be calculated using the ideal gas law, which states that PV = nRT. In this case, P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature. We know that the volume of the container is 2.0 L, the number of moles of gas is 9.0 g / 18 g/mol = 0.5 mol, the ideal gas constant is 0.082 L · atm/mol · K, and the temperature is 300°C = 573 K. Plugging these values into the ideal gas law, we get P = nRT/V = (0.5 mol)(0.082 L · atm/mol · K)(573 K) / (2.0 L) = 12 atm.

90 G of Water in a 2