In an isobaric process 3.6 × 10⁴ J of work is done on a quantity of gas while its volume changes from 2.3 m³ to 1.1 m³.What is the pressure during this process? A) 1.2 × 10⁴ Pa B) 2.4 × 10⁴ Pa C) 3.0 × 10⁴ Pa D) 8.3 × 10⁴ Pa

Question

Quizplus · Accepted Answer

In an isobaric process, the pressure remains constant. Therefore, from the work done equation:
work = pressure x change in volume
we can solve for the pressure:
pressure = work / change in volume
Substituting the given values:
pressure = 3.6 × 10^14 J / ((1.1 - 2.3) m^3)
pressure = -3.6 × 10^14 J / (1.2 m^3)   (Note: negative sign indicates work is done on the gas)
pressure = 3.0 × 10^14 Pa

In an Isobaric Process 3