When charges q_a,q_b,and q_c are placed respectively at the corners a,b,and c of a right triangle,the potential at the midpoint of the hypotenuse is 22 V.When the charge q_a is removed,the potential at the midpoint becomes 15 V.When,instead,the charge q_b is removed (q_a and q_c both in place),the potential at the midpoint becomes 13 V.What is the potential at the midpoint if both charges q_a and q_c are removed? A) 9 V B) 7 V C) 6 V D) 16 V E) 15 V

Question

Quizplus · Accepted Answer

The potential at the midpoint of the hypotenuse is due to the charges at the corners a, b, and c. When q_a is removed, the potential at the midpoint decreases by 7 V, which means that q_a contributes 7 V to the potential at the midpoint. Similarly, when q_b is removed, the potential at the midpoint decreases by 9 V, which means that q_b contributes 9 V to the potential at the midpoint. Therefore, when both q_a and q_c are removed, the potential at the midpoint will decrease by 7 V + 9 V = 16 V. Since the potential at the midpoint is initially 22 V, the potential at the midpoint when both q_a and q_c are removed will be 22 V - 16 V = 6 V.

When Charges Qa,qb,and Qc Are Placed Respectively at the Corners

When Charges Q_a,q_b,and Q_c Are Placed Respectively at the Corners