A flashlight bulb operating at a voltage of 3 V has a resistance of 10 Ω.How many electrons pass through the bulb filament per second (e = 1.6 × 10−¹⁹ C)? A) 0.5 × 10¹⁶ B) 4.8 × 10²¹ C) 5.3 × 10¹⁷ D) 1.9 × 10¹⁸ E) 2.1 × 10²⁰

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Quizplus · Accepted Answer

The current (I) can be calculated using Ohm's Law: I = V/R = 3V/10Ω = 0.3A. The number of electrons per second is I/e = 0.3A / (1.6 × 10^-19 C) = 1.875 × 10^18, which is approximately 1.9 × 10^18.

A Flashlight Bulb Operating at a Voltage of 3 V