Carbon has a negative temperature coefficient of resistance of -0.5 × 10^-3 (°C)−¹.What temperature increase would result in a resistance decrease of 4% for a carbon resistor? A) 8°C B) 80°C C) 19°C D) 13°C E) 400°C

Question

Quizplus · Accepted Answer

The resistance change is given by ΔR/R = αΔT, where α is the temperature coefficient. For a 4% decrease, ΔR/R = -0.04. Solving -0.04 = -0.5 × 10^-3 × ΔT gives ΔT = 80°C.

Carbon Has a Negative Temperature Coefficient of Resistance of -0