A uniform electric field,with a magnitude of 600 N/C,is directed parallel to the positive x axis.If the potential at x = 4.0 m is 1000 V,what is the potential at x = 2.0 m?
A) −800 V
B) 2200 V
C) 2800 V
D) 1600 V

Question

Quizplus · Accepted Answer

The potential difference in a uniform electric field is given by V = Ed, where E is the electric field and d is the distance. The potential decreases in the direction of the field. So, V(2.0 m) = V(4.0 m) + E*(4.0 m - 2.0 m) = 1000 V + 600 N/C * 2.0 m = 2200 V.

A Uniform Electric Field,with a Magnitude of 600 N/C,is Directed