A 6.0-μF capacitor is attached to a 20-V power supply.How much energy is stored in the capacitor? A) 2.0 × 10−³ J B) 5.2 × 10−⁴ J C) 2.0 × 10−⁴ J D) 1.2 × 10−³ J

Question

Quizplus · Accepted Answer

The energy stored in a capacitor is given by the formula $ E = \frac{1}{2} C V^2 $. Substituting the given values, $ C = 6.0 \times 10^{-6} \, \text{F} $ and $ V = 20 \, \text{V} $, we get $ E = \frac{1}{2} \times 6.0 \times 10^{-6} \times (20)^2 = 1.2 \times 10^{-3} \, \text{J} $.

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