Three resistors,with values of 4,6 and 15 Ω,respectively,are connected in parallel.What is the overall resistance of this combination?
A) 25 Ω
B) 2.1 Ω
C) 0.48 Ω
D) 8.3 Ω
E) 7.1 Ω

Question

Three resistors,with values of 4,6 and 15 Ω,respectively,are connected in parallel.What is the overall resistance of this combination?
A) 25 Ω
B) 2.1 Ω
C) 0.48 Ω
D) 8.3 Ω
E) ​7.1 Ω

Quizplus · Accepted Answer

The formula for total resistance $ R_t $ in parallel is $ \frac{1}{R_t} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} $. Substituting the given values: $ \frac{1}{R_t} = \frac{1}{4} + \frac{1}{6} + \frac{1}{15} = \frac{15}{60} + \frac{10}{60} + \frac{4}{60} = \frac{29}{60} $. Thus, $ R_t = \frac{60}{29} \approx 2.1 $ Ω.

Three Resistors,with Values of 4,6 and 15 Ω,Respectively,are Connected in Parallel.What