If a metallic wire of cross-sectional area 3.0 × 10−⁶ m² carries a current of 9.1 A and has a mobile charge density of 4.24 × 10²⁸ carriers/m³,what is the average drift velocity of the mobile charge carriers? (charge value = 1.6 × 10−¹⁹ C) A) 3.4 × 10³ m/s B) 1.7 × 10³ m/s C) 4.5 × 10−⁴ m/s D) 1.5 × 10−⁴ m/s

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Quizplus · Accepted Answer

The drift velocity (v_d) can be calculated using the formula: v_d = I / (n * A * e), where I is the current, n is the charge density, A is the cross-sectional area, and e is the charge of an electron. Substituting the given values: v_d = 9.1 / (4.24 × 10^28 * 3.0 × 10^-6 * 1.6 × 10^-19) = 4.5 × 10^-4 m/s.

If a Metallic Wire of Cross-Sectional Area 3