A proton is released such that it has an initial speed of 3.7 × 10⁵ m/s from left to right across the page.A magnetic field of 1.5 T is present at an angle of 18° to the horizontal direction (or positive x axis).What is the magnitude of the force experienced by the proton? (q_p = 1.6 × 10−¹⁹ C)

Question

Quizplus · Accepted Answer

The magnetic force on a moving charge is given by F = qvBsinθ. Substituting the given values: F = (1.6 × 10^-19 C)(3.7 × 10^5 m/s)(1.5 T)sin(18°) = 2.7 × 10^-14 N.

A Proton Is Released Such That It Has an Initial