A current-carrying wire of length 42 cm is positioned perpendicular to a uniform magnetic field.If the current is 6.7 A and it is determined that there is a resultant force of 2.9 N on the wire due to the interaction of the current and field,what is the magnetic field strength?

Question

Quizplus · Accepted Answer

The magnetic force on a current-carrying wire is given by F = BIL, where F is the force, B is the magnetic field strength, I is the current, and L is the length of the wire. Rearranging for B gives B = F / (IL). Substituting the given values: B = 2.9 N / (6.7 A * 0.42 m) = 1.03 T.

A Current-Carrying Wire of Length 42 Cm Is Positioned Perpendicular