A high-voltage power line 26.9 m above the ground carries a current of 2722 A.What is the magnetic field due to the current directly underneath the power line? (µ₀ = 4π × 10−⁷ T⋅m/A)

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The magnetic field due to a long straight current-carrying wire is given by B = (µ₀I)/(2πr). Substituting the given values: µ₀ = 4π × 10⁻⁷ T⋅m/A, I = 2722 A, and r = 26.9 m, we get B = (4π × 10⁻⁷ T⋅m/A × 2722 A)/(2π × 26.9 m) = 20.2 µT.

A High-Voltage Power Line 26