Two parallel wires are separated by 0.43 m.Wire A carries 3.3 A and Wire B carries 8.3 A,both currents in the same direction.The force on 0.90 m of Wire A is:

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The force between two parallel wires is given by:F = (μ0 * I1 * I2 * L) / (2π * d)where:μ0 is the permeability of free space (4π × 10^-7 T·m/A)I1 and I2 are the currents in the wires (in amperes)L is the length of the wires (in meters)d is the distance between the wires (in meters)Plugging in the given values, we get:F = (4π × 10^-7 T·m/A) * (3.3 A) * (8.3 A) * (0.90 m) / (2π * 0.43 m)F = 1.1 × 10^-5 NTherefore, the force on 0.90 m of Wire A is 1.1 × 10^-5 N.

Two Parallel Wires Are Separated by 0