Superconductors can carry very large currents with no resistance.If a superconducting wire is formed into a solenoid of length 74.6 cm with 660 turns,what is the magnetic field inside the solenoid when the current is 6.5 kA? (µ₀ = 4π × 10−⁷ T⋅m/A)

Question

Quizplus · Accepted Answer

We can use the formula for magnetic field inside a solenoid:

B = µN*I / L

Where µ is the permeability of free space, N is the number of turns, I is the current, and L is the length of the solenoid.

Plugging in the given values, we get:

B = (4π×10^-7 T⋅m/A) * 660 * 6.5 kA / 0.746 m

Simplifying, we get:

B = 7.23 T

Therefore, the answer is D, 7.23 T.

Superconductors Can Carry Very Large Currents with No Resistance