A horizontal wire of length 3.6 m carries a current of 6.0 A and is oriented so that the current direction is 50° S of W.The Earth's magnetic field is due north at this point and has a strength of 0.14 × 10−⁴ T.What is the size of the force on the wire? A) 1.6 × 10−⁴ N B) 0.28 × 10−⁴ N C) 1.9 × 10−⁴ N D) 2.5 × 10−⁴ N

Question

Quizplus · Accepted Answer

The force on the wire can be calculated using the formula F = IBLsinθ, where I is the current, B is the magnetic field strength, L is the length of the wire, and θ is the angle between the current direction and the magnetic field direction. Plugging in the given values, we get F = (6.0 A)(0.14 × 10−5 T)(3.6 m)sin(50°) = 1.9 × 10−5 N. Therefore, the correct answer is C.

A Horizontal Wire of Length 3