A loop of area 0.120 m² is in a uniform 0.0500-T magnetic field.If the flux through the loop is 4.09 × 10^-3 T·m²,what angle does the normal to the plane of the loop make with the direction of the magnetic field? A) 47.0° B) 83.5° C) 43.0° D) 79.1º E) This is not possible.

Question

Quizplus · Accepted Answer

The magnetic flux (Φ) is given by Φ = B * A * cos(θ), where B is the magnetic field, A is the area, and θ is the angle between the magnetic field and the normal to the loop. Solving for θ, we get cos(θ) = Φ / (B * A) = 4.09 × 10^-3 / (0.0500 * 0.120) = 0.6817. Therefore, θ = cos^(-1)(0.6817) ≈ 47.0°.

A Loop of Area 0